10c^2-13c+4=0

Solution for 10c^2-13c+4=0 equation:

Simplifying
10c2 + -13c + 4 = 0

Reorder the terms:
4 + -13c + 10c2 = 0

Solving
4 + -13c + 10c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(1 + -2c)(4 + -5c) = 0

Subproblem 1
Set the factor '(1 + -2c)' equal to zero and attempt to solve:

Simplifying
1 + -2c = 0

Solving
1 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2c = 0 + -1
-2c = 0 + -1

Combine like terms: 0 + -1 = -1
-2c = -1

Divide each side by '-2'.
c = 0.5

Simplifying
c = 0.5
Subproblem 2
Set the factor '(4 + -5c)' equal to zero and attempt to solve:

Simplifying
4 + -5c = 0

Solving
4 + -5c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -5c = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -5c = 0 + -4
-5c = 0 + -4

Combine like terms: 0 + -4 = -4
-5c = -4

Divide each side by '-5'.
c = 0.8

Simplifying
c = 0.8
Solution
c = {0.5, 0.8}